When performing any type of work, the question arises: "What material will be needed and how much?".No exception and plasterboard ceiling.
will now be considered by the calculation of ceilings for the proper determination of the amount of material.Photos, which are listed below, to help better navigate in the materials.
calculation of components and ceiling area
For some, it may seem strange given instruction on product calculations.They can understand, but it is one thing to calculate the amount of drywall (plasterboard ceiling sm.Raschet - competently and correctly) according to the surface area of the roof, and quite another - the calculation of the ceiling.
After all, this will require not only the ceiling drywall, but also a lot of other stuff.
Calculation of materials
ability to correctly calculate the required mounting material help in the repair of their own hands.
- Note that the size of the premisesdoes not match the size of a sheet of drywall, therefore, the installation would have to cut sheets or cut some items.
- Also, it is important to understand that the gypsum boards are attached not only to the ceiling, they are mounted on a metal frame (sm.Karkas ceiling plasterboard - all the little things or little things do not happen.).And customized and cut sheets must be such that their joint necessarily lying on the profile frame.
Otherwise cracks in the ceiling.
- immediately without making measurements, it is impossible to determine the amount of material that you will need. You can buy most certainly necessary, but it makes no sense.
Why take more than necessary?
now calculate the necessary amount of material for a simple one-level ceiling.First of all, it measures the area of the premises.
Take for example the room 5500 mm long and 3200 mm wide.Rooms often have a rectangular shape.
In our example, the room has the same wall, hence its angles are 90 °, it is worth paying attention, becauseit may be that one wall is wider than the other, and corners, respectively, will not be 90 °, in such a case, the calculation is made for the width.
Returning to our example.
made calculations perimeter:
- P = (5500 + 3200) x2 = 17400 mm;
- Then you can calculate how much you need to UD-27 profile.
see the number of profile UD-27, which is required. standard length of this profile is 3000 or 4000 mm.
If you take the profile of 3000 mm, the width of the room 3200 mm will need to add 200 mm, which is inconvenient.It is better to acquire the profile of 4000 mm Dina.Following
already made the calculation, it is easy to know the number of profiles:
- 17400/4000 = 4,35
It turns out that, in this room need 5 pcs.profiles UD-27 4 m.
Calculation of profile CD-60
must now count the number of the frame profile for CD-60 .You must pay attention to the size of a sheet of drywall.
standard gypsum boards are of such size:
- 1200h2500h9,5 mm
- 1200h3000h12,5 mm
- 1200h2500h12,5 mm
Price, respectively, in the various different sheets.
Tip!It is also necessary to determine the direction of the profile.The frame should be mounted across the width.
This location is the most economical gypsum board that will provide the least amount of waste.
width of the ceiling in the room 3200 mm, width 1200 mm plasterboard. Profile, necessarily, should go in the middle and on the edges of the sheet, all three of them, therefore, a step of 600 mm.
Profile starts at one wall and at the opposite end. expect:
- 5500/600 = 9,1
get 9 pieces 600h9 = 5400 mm, and the final profile will be set at the level of - 5400, there is still 100 to the wall, but the step 600mm, it is not terribly more profile areas not nuzhno.U width 3200, length 4000 profile, therefore, with each profile will remain at 800 mm, but it will still be necessary.
Determining the height of the ceiling
When installing ceiling drywall, you need to determine at what distance from the main ceiling will be its installation.Depending on the size of the selected elements of the fastener.
minimum possible distance - 27 mm, the width of UD-27 profile, and the maximum distance to the right standard suspension of 120 mm.
Tip!When you want to install a false ceiling at a greater distance, using a spring hanger wire.Thus the suspension may be omitted design 500 mm or more from the basic ceiling.
Example confine ourselves to the fact that the ceiling does not fall below 120 mm from the main overlap.
now calculated the number of hangers to the ceiling
first suspension is set at a distance from wall 300 mm, then they are attached as well as the profile - every 600 mm. Consequently, one profile is necessary to five suspensions.
In our construction of nine profiles, then:
- 9x5 = 45
We need 45 pieces of direct suspensions.
on the primary carrier profile, set the jumpers, which are made of profile CD-60 of the same which was used for the main bearing.They are joined by a crab.
Crabs also installed every 600 mm between the fixed suspensions, hence the need to profile one of four crab count:
- 4x9 = 36
So, you need 36 crabs.
counts the number of jumpers.
profile CD-60, has a width of 60 mm, then deduct 30 mm twice (on each side of the distance between the profiles):
- 600- (30x2) = 540 mm
necessary to take another 5mm, to avoid problems during assembly, we obtain 535 mm.Also measure the distance between the profile and crab UD-27.At the beginning of installation this distance equals 600 mm, on the other hand - 100 mm.
received two sizes:
- (600-30) -5 = 565 mm
- (100-30) -5 = 65 mm
therefore need 4 pieces 65 mm long, 4565 mm long pieces and 36 pieces of 535 mm length.
We had nine pieces of 800 mm.One will go to the four bridges and one 65 mm - 535 mm.Of the remaining eight
uses four 565 mm, and the last four - 535 mm.
- 535h31 = 16585 mm
Take the profile - a three-meter.
- 16585/3000 = 5,52
Therefore, we still have six three-meter sections.
summarize, calculated the false ceiling, it became known quantity of material required:
- Profiles UD-27 - 5 pieces.4 m;
- Profiles CD-60 - 9 pcs.4 m;
- Profiles CD-60 - 6 pieces.3 m;
- suspension lines - 45 pcs .;
- Crabs - 36 pcs.
calculation is made according to the drywall ceiling area, it is easy to calculate that we need six single sheet of plasterboard 1250 x 2500 x 9,5.
Knowing the exact number of pages, define the number of screws.Plasterboard attached to profiles screws every 250 mm.A mounting frame required more dowels (every 300-400 mm) and screws for attachment to the suspension profile (6 per crab and 4 on the suspension).
With P = 17400/300 = 58 dowels.
- 45h4 = 180 pcs.on the suspension.
- 36h6 = 216 pcs.Krabi.
Knowing the bases of calculation, you do not have to buy the material, which did not have or obtain the remains of repairs.Reinforce their knowledge in this area can be looking at YouTube videos.
This will easily make the necessary calculations.Suspended ceiling you will be sure to do yourself.